1002. A+B for Polynomials (25)

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This time, you are supposed to find A+B where A and B are two polynomials.

Input

Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N1 aN1 N2 aN2 … NK aNK, where K is the number of nonzero terms in the polynomial, Ni and aNi (i=1, 2, …, K) are the exponents and coefficients, respectively. It is given that 1 <= K <= 10，0 <= NK < … < N2 < N1 <=1000.

Output

For each test case you should output the sum of A and B in one line, with the same format as the input. Notice that there must be NO extra space at the end of each line. Please be accurate to 1 decimal place.

Sample Input

2 1 2.4 0 3.2
2 2 1.5 1 0.5

Sample Output

3 2 1.5 1 2.9 0 3.2

思路：题意是根据输入的两个多项式相加后，输出相加后多项式的项数和结果，注意两个多项式相加后系数为0的情况。

Code：

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using namespace std;
int main()
{
    int i;
    float pol[1100];
    for(i=0;i<1100;++i)
        pol[i]=0.0;
    int k,temp1;
    float temp2;
    cin>>k;
    for(i=0;i<k;++i)
    {
        cin>>temp1;
        cin>>pol[temp1];
    }
    int cnt=k;
    cin>>k;
    for(i=0;i<k;++i)
    {
        cin>>temp1>>temp2;
        if(pol[temp1]==0.0)
        {
            ++cnt;
            pol[temp1]=temp2;
        }
        else
            pol[temp1]+=temp2;
        if(pol[temp1]==0.0)//如果相加后系数为0，总个数减一
            --cnt;
    }
    cout<<cnt;
    for(i=1099;i>=0;--i)
    {
        if(pol[i]!=0.0)
            printf(" %d %.1f",i,pol[i]);
    }
    return 0;
}

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