Blocks

Description

Donald wishes to send a gift to his new nephew, Fooey. Donald is a bit of a traditionalist, so he has chosen to send a set of N classic baby blocks. Each block is a cube, 1 inch by 1 inch by 1 inch. Donald wants to stack the blocks together into a rectangular solid and wrap them all up in brown paper for shipping. How much brown paper does Donald need?

Input

The first line of input contains C, the number of test cases. For each case there is an additional line containing N, the number of blocks to be shipped. N does not exceed 1000.

Output

Your program should produce one line of output per case, giving the minimal area of paper (in square inches) needed to wrap the blocks when they are stacked together.

Sample Input

5
9
10
26
27
100

Sample Output

30
34
82
54
130

分析:枚举,堆积起来的体积为ijk,则num%(i*j)肯定为整数,然后更新表面积得到最小即可。

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
#include<iostream>
#include<algorithm>
#include<vector>
#include<cctype>
#include<cmath>
#include<cstring>
#include<cstdio>
using namespace std;
void solve();
int main()
{
solve();
return 0;
}
void solve()
{
int t,i,j,m,num,ans,now;
cin>>t;
while(t--)
{
ans=999999999;
cin>>num;
for(i=1;i<=num;i++)
{
for(j=1;j*i<=num;j++)
{
if(num%(i*j)!=0)
continue;
m=num/(i*j);
now=i*j+i*m+m*j;
if(now<ans)
ans=now;
}
}
cout<<ans*2<<endl;
}
}

打个小广告

欢迎加入我的知识星球「基你太美」,我会在星球中分享 AucFrame 框架、大厂面经、AndroidUtilCode 更详尽的说明…一切我所了解的知识,你可以通过支付进入我的星球「基你太美」进行体验,加入后优先观看星球中精华的部分,如果觉得星球的内容对自身没有收益,你可以自行申请退款退出星球,也没必要加我好友;如果你已确定要留在我的星球,可以通过扫描如下二维码(备注:基你太美+你的星球昵称)加我个人微信,方便我后续拉你进群(PS:进得越早价格越便宜)。

我的二维码